16x^2+8x-53=-5

Solution for 16x^2+8x-53=-5 equation:

16x^2+8x-53=-5

We move all terms to the left:

16x^2+8x-53-(-5)=0

We add all the numbers together, and all the variables

16x^2+8x-48=0

a = 16; b = 8; c = -48;
Δ = b2-4ac
Δ = 82-4·16·(-48)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*16}=\frac{-64}{32}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*16}=\frac{48}{32}
=1+1/2
$